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-1.5x^2-10.5x+90=0
a = -1.5; b = -10.5; c = +90;
Δ = b2-4ac
Δ = -10.52-4·(-1.5)·90
Δ = 650.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10.5)-\sqrt{650.25}}{2*-1.5}=\frac{10.5-\sqrt{650.25}}{-3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10.5)+\sqrt{650.25}}{2*-1.5}=\frac{10.5+\sqrt{650.25}}{-3} $
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